$${S_\text{Al} = \frac{\pi d^2}{4} + \pi d h = \frac{(3,14) (0,06^2\, \mathrm{m^2})}{4} + (3,14) (0,06\, \mathrm{m}) (0,07\, \mathrm{m}) = 0,016\, \mathrm{m^2}}$$