$${\frac{\Delta{l}}{m}=\frac{11,1\,\text{cm}}{110\,\text g} \approx 0,10\,\frac{\text{cm}}{\text g}=0,10 \,\frac{10^{-2}\,\text m}{10^{-3}\,\text {kg}}=1,0 \,\frac{\text m}{\text {kg}}}$$